## Physics: Principles with Applications (7th Edition)

a. $6.1 \times 10^6 \frac{N}{m^2}$ b. $1.7 \times 10^5 \frac{N}{m^2}$
The downward force is equal to half the person’s weight. a. $P_{pointed}=\frac{(0.5)(56kg)(9.80m/s^2)}{0.45 \times 10^{-4}m^2}=6.1 \times 10^6 \frac{N}{m^2}$ b. $P_{flat}=\frac{(0.5)(56kg)(9.80m/s^2)}{16 \times 10^{-4}m^2}=1.7 \times 10^5 \frac{N}{m^2}$