## Physics: Principles with Applications (7th Edition)

$4.3 \times 10^5 N/m^2$
The minimum gauge pressure supports a column of water of this height. Use equation 10–3a, and round the answer to 2 significant figures. $$P_G=\rho gh = (1.00 \times 10^3 kg/m^3)(9.80 m/s^2)(44m)=4.3 \times 10^5 N/m^2$$