Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - Problems: 19

Answer

The height of the atmosphere would be 16.0 km

Work Step by Step

The density of air at sea level is $1.29~kg/m^3$. Half of this value is $0.645~kg/m^3$. We know that the pressure at the Earth's surface is $1.01\times 10^5~Pa$. We can find the height of the atmosphere. $P = \rho~g~h$ $h = \frac{P}{\rho~g}$ $h = \frac{1.01\times 10^5~N/m^2}{(0.645~kg/m^3)(9.80~m/s^2)}$ $h = 1.60 \times 10^4~m = 16.0~km$ The height of the atmosphere would be 16.0 km
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