## Physics: Principles with Applications (7th Edition)

The pressure difference is due to the depth of water. Use equation 10–3b, and round the answer to 2 significant figures. $$\Delta P=\rho g \Delta h$$ $$\Delta h= \frac{\Delta P}{\rho g}$$ $$=\frac{(85 mm-Hg)((133 N/m^2)/(1mm-Hg))}{(1.00 \times 10^3 kg/m^3)(9.80 m/s^2)} \approx 1.2m$$ His maximum depth would be about 1.2 m.