Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - Problems - Page 285: 6

Answer

The specific gravity of the mixture is 0.91

Work Step by Step

We can find the mass $M_a$ of the antifreeze solution. $M_a = (0.80)(1.000\times 10^3~kg/m^3)(10^{-3}~m^3/L)(4.0~L)$ $M_a = 3.2~kg$ We can find the mass $M_w$ of the water. $M_w = (1.000\times 10^3~kg/m^3)(10^{-3}~m^3/L)(5.0~L)$ $M_a = 5.0~kg$ The total mass of the mixture is 8.2 kg. We can find the density of the mixture. $\rho = (\frac{8.2~kg}{9.0~L})~(\frac{1~L}{10^{-3}~m^3})$ $\rho = 0.91\times 10^3~kg/m^3$ The specific gravity of the mixture is 0.91
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