Answer
1.0 m.
Work Step by Step
Use equation 10–3b to relate the difference in pressure to the height of the column of water.
$$\Delta P = \rho g \Delta h$$
$$\Delta h = \frac{\Delta P }{\rho g }=\frac{(75\;mm-Hg)(\frac{133\;N/m^2}{1\;mm-Hg})}{(1.00\times10^3\;kg/m^3)(9.80\;m/s^2)}\approx1.0\;m$$