Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - General Problems - Page 289: 81

Answer

1.0 m.

Work Step by Step

Use equation 10–3b to relate the difference in pressure to the height of the column of water. $$\Delta P = \rho g \Delta h$$ $$\Delta h = \frac{\Delta P }{\rho g }=\frac{(75\;mm-Hg)(\frac{133\;N/m^2}{1\;mm-Hg})}{(1.00\times10^3\;kg/m^3)(9.80\;m/s^2)}\approx1.0\;m$$
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