Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - General Problems - Page 289: 76

Answer

0.048 atm.

Work Step by Step

Use equation 10–3b to calculate the change in pressure, then divide by atmospheric pressure. $$\Delta P = \rho g \Delta h$$ $$\frac{\Delta P}{P_o} = \frac{\rho g \Delta h}{1.013\times10^5\;Pa}$$ $$= \frac{(1.29\;kg/m^3) (9.80\;m/s^2) (380\;m)}{1.013\times10^5\;Pa}=0.048$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.