Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 10 - Fluids - General Problems - Page 289: 74

Answer

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Work Step by Step

a. This is a gauge pressure, measured relative to atmospheric pressure. The pressure change due to depth in a fluid is given by equation 10–3b. $$\Delta P = \rho g \Delta h$$ $$\Delta h = \frac{\Delta P}{\rho g }= \frac{(52\;mm-Hg)(\frac{133\;N/m^2}{1\;mm-Hg})}{(1000\;kg/m^3)(9.8\;m/s^2)}=0.71\;m$$ b. This is a gauge pressure, measured relative to atmospheric pressure. The pressure change due to depth in a fluid is given by equation 10–3b. $$\Delta P = \rho g \Delta h$$ $$\Delta h = \frac{\Delta P}{\rho g }= \frac{(680\;mm-H_2O)(\frac{9.8\;N/m^2}{1\;mm-H_2O})}{(1000\;kg/m^3)(9.8\;m/s^2)}=0.68\;m$$ c. For the fluid to just barely enter the vein, the fluid pressure equals the blood pressure. $$\Delta h = \frac{\Delta P}{\rho g }= \frac{(75\;mm-Hg)(\frac{133\;N/m^2}{1\;mm-Hg})}{(1000\;kg/m^3)(9.8\;m/s^2)}=1.0\;m$$
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