Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 1 - Introduction, Measurement, Estimating - General Problems - Page 20: 47

Answer

It would take 75 minutes to read all the data on the CD.

Work Step by Step

A CD has (783.216)(8) megabits of data. The time required to read all this data is: $\frac{(783.216)(8)}{1.4} = 4475.52~s$ $(4475.52 ~s)(\frac{1 ~min}{60 ~s}) = 75$ minutes It would take 75 minutes to read all the data on the CD.
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