#### Answer

(a) $W = 9.8\times 10^5~J$
(b) $P = 1.96\times 10^4~watts$

#### Work Step by Step

(a) Since the elevator moves at a constant speed, the tension in the elevator cable is equal in magnitude to the weight of the elevator. We can find the work done by the motor as;
$W = T~d$
$W = (mg)~d$
$W = (1000~kg)(9.80~m/s^2)(100~m)$
$W = 9.8\times 10^5~J$
(b) We can find the power supplied by the motor;
$P = \frac{W}{t}$
$P = \frac{9.8\times 10^5~J}{50~s}$
$P = 1.96\times 10^4~watts$