#### Answer

The power increases by a factor of 4.

#### Work Step by Step

Let $h$ be the height that the beam was lifted initially. The work done by the motor is equal to the increase in potential energy. That is: $W_1 = mgh$
We can write an expression for the power in the initial case.
$P = \frac{W_1}{t}$
Let's suppose that the beam is lifted to twice the height. We can find an expression for the work done by the motor.
$W_2 = mg~(2h) = 2~W_1$
We can write an expression for the power in the second case.
$P_2 = \frac{W_2}{t/2}$
$P_2 = \frac{4~W_1}{t}$
$P_2 = 4~P$
The power increases by a factor of 4.