Answer
Block A's acceleration in case b is greater than block A's acceleration in case a.
Work Step by Step
Consider a free-body diagram for the 10-N block in case a. Since the 10-N block is accelerating downward, the tension in the string must be less than 10 N. Therefore, the tension in the string pulling block A in case a is less than the tension in the string pulling block A in case b. Therefore, block A's acceleration in case b is greater than block A's acceleration in case a.