## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Since the sled moves at a steady speed, the acceleration is zero, so the net force on the sled is also zero. The sum of the forward-pointing component $F_x$ of each player's force $F$ must be equal in magnitude to the friction force. Therefore; $2~F_x = F_f$ $2~F~cos(10^{\circ}) = F_f$ $F = \frac{1000~N}{2~cos(10^{\circ})}$ $F = 508~N$ Each player must pull with a force of 508 N