Answer
$a = -2.8~m/s^2$
Work Step by Step
$a = \frac{v^2-v_0^2}{2x}$
$a = \frac{(6.0~m/s)^2-(8.0~m/s)^2}{(2)(5.0~m)}$
$a = -2.8~m/s^2$
Magnitude = $ 2.8~m/s^2$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 2 - Kinematics in One Dimension - Exercises and Problems - Page 60: 17
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