Answer
The ice cube goes up to a height of 0.26 m
Work Step by Step
The block's potential energy at the maximum height will be equal to the initial energy stored in the spring. We can find the maximum height $h$ as:
$PE = U_s$
$mgh = \frac{1}{2}k(\Delta x)^2$
$h = \frac{k~(\Delta x)^2}{2mg}$
$h = \frac{(25~N/m)(0.10~m)^2}{(2)(0.050~kg)(9.80~m/s^2)}$
$h = 0.26~m$
The ice cube goes up to a height of 0.26 m.
