Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 10 - Interactions and Potential Energy - Exercises and Problems - Page 257: 38

Answer

$K_f = 2~J$

Work Step by Step

We can use conservation of energy to find $K_f$: $K_i+U_i+W_{ext} = K_f+U_f+\Delta E_{th}$ $K_f = K_i+U_i+W_{ext} -U_f-\Delta E_{th}$ $K_f = (1~J)+(1~J)+(4~J) -(3~J)-(1~J)$ $K_f = 2~J$
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