Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 10 - Interactions and Potential Energy - Exercises and Problems: 17

Answer

The book slides away with a speed of 2.0 m/s

Work Step by Step

The book's kinetic energy when it slides away from the spring will be equal to the energy $U_s$ stored in the spring initially. We can find the speed of the book. $KE = U_s$ $\frac{1}{2}mv^2=\frac{1}{2}kx^2$ $v^2=\frac{kx^2}{m}$ $v=\sqrt{\frac{kx^2}{m}}$ $v=\sqrt{\frac{(1250~N/m)(0.040~m)^2}{0.500~kg}}$ $v = 2.0~m/s$ The book slides away with a speed of 2.0 m/s.
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