Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 9 - Impulse and Momentum - Exercises and Problems: 24

Answer

$p_x$ of the third fragment is -1 N s $p_y$ of the third fragment is -2 N s

Work Step by Step

We can use conservation of momentum to find the components of the third fragment's momentum. Since the initial momentum of the object is zero, the final momentum is also zero. Let's consider the horizontal components of momentum. $p_{1x}+p_{2x}+p_{3x} = 0$ $p_{3x} = -p_{1x}-p_{2x}$ $p_{3x} = -(-2~N~s)-(3~N~s)$ $p_{3x} = -1~N~s$ $p_x$ of the third fragment is -1 N s. Let's consider the vertical components of momentum. $p_{1y}+p_{2y}+p_{3y} = 0$ $p_{3y} = -p_{1y}-p_{2y}$ $p_{3y} = -(2~N~s)-0$ $p_{3y} = -2~N~s$ $p_y$ of the third fragment is -2 N s.
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