Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 8 - Dynamics II: Motion in a Plane - Exercises and Problems: 34

Answer

The coin will not slide off.

Work Step by Step

We can find the maximum possible force of static friction. $F_f = mg~\mu_s$ $F_f = (0.0050~kg)(9.80~m/s^2)(0.80)$ $F_f = 0.0392~N$ We can find the speed of the coin as it rotates at a rate of 60 rpm. $v = (60~rpm)(2\pi~r)(\frac{1~min}{60~s})$ $v = (60~rpm)(2\pi)(0.15~m)(\frac{1~min}{60~s})$ $v = 0.942~m/s$ We can find the centripetal force required to keep the coin moving around in a circle. $F_c = m~\frac{v^2}{r}$ $F_c = (0.0050~kg)~\frac{(0.942~m/s)^2}{0.15~m}$ $F_c = 0.0296~N$ Since the maximum force of static friction on the coin is greater than the required force to keep the coin moving around in a circle, the coin will not slide off.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.