Chapter 6 - Dynamics I: Motion Along a Line - Exercises and Problems - Page 164: 60

No

lets first calculate deceleration of the puck $2as = v^2 -u^2$ $2*a*3 = 4^2 -5^2$ $a= -3/2 ms^{-2}$ now total distance travelled by the puck $ 2as = v^2 -u^2$ $2*(-3/2) *s = 0 - 5^2$ $ 3s = 25$ $ s=8.33$ since the distance between the puck and end point is greater than $10cm$, we will not be winner