## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

(a) $a = 16~m/s^2$ (b) $a = 4.0~m/s^2$ (c) $a = 8.0~m/s^2$ (d) $a = 32~m/s^2$
$F = ma$ can be written as: $a = \frac{F}{m}$ Then, we find $a$: $a = \frac{F}{m} = 8.0~m/s^2$ (a) $a = \frac{(2F)}{m} = (2)(8.0~m/s^2) = 16~m/s^2$ (b) $a = \frac{F}{(2m)} = \frac{8.0~m/s^2}{2} = 4.0~m/s^2$ (c) $a = \frac{(2F)}{(2m)} = \frac{F}{m} = 8.0~m/s^2$ (d) $a = \frac{(2F)}{(m/2)} = \frac{4F}{m} = (4)(8.0~m/s^2) = 32~m/s^2$