Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 38 - Quantization - Exercises and Problems - Page 1152: 18

Answer

$K = 8.2~MeV$

Work Step by Step

We can find an expression for the speed: $\lambda = \frac{h}{m~v}$ $v = \frac{h}{m~\lambda}$ We can find the kinetic energy: $K = \frac{1}{2}mv^2$ $K = (\frac{1}{2})(m)(\frac{h}{m~\lambda})^2$ $K = \frac{h^2}{2~m~\lambda^2}$ $K = \frac{(6.626\times 10^{-34}~J~s)^2}{(2)(1.67\times 10^{-27}~kg)~(10\times 10^{-15}~m)^2}$ $K = 1.3145\times 10^{-12}~J$ $K = (1.3145\times 10^{-12}~J)(\frac{1~eV}{1.6\times 10^{-19}~J})$ $K = 8.2\times 10^6~eV$ $K = 8.2~MeV$
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