Answer
(a) $1.49\times 10^{29}~photons/s$
(b) We should treat the broadcast as an electromagnetic wave.
Work Step by Step
(a) We can find the energy of each photon:
$E = h~f$
$E = (6.626\times 10^{-34}~J~s)(101\times 10^6~Hz)$
$E = 6.69226\times 10^{-26}~J$
We can find the number of photons emitted each second:
$\frac{10,000~W}{6.69226\times 10^{-26}~J} = 1.49\times 10^{29}~photons/s$
(b) With such an enormous number of photons emitted each second, it would be overwhelming to treat the broadcast as discrete photons. It is much more reasonable to treat the broadcast as an electromagnetic wave.
