Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 37 - The Foundations of Modern Physics - Exercises and Problems - Page 1122: 29

Answer

$K = 174~MeV$

Work Step by Step

We can find the kinetic energy: $K = mc^2$ $K = (0.185)(1.67\times 10^{-27}~kg)(3.0\times 10^8~m/s)^2$ $K = 2.78\times 10^{-11}~J$ $K = (2.78\times 10^{-11}~J)(\frac{1~eV}{1.6\times 10^{-19}~J})$ $K = 1.74\times 10^{8}~eV$ $K = 174\times 10^{6}~eV$ $K = 174~MeV$
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