Answer
(a) $^{11}B$
(b) $^{14}C^+$
Work Step by Step
(a) If there are five protons, then it is boron.
If there are six neutrons and five protons, then there are eleven nucleons.
If there are five electrons, then the charge is neutral.
We can write the symbol for this atom:
$^{11}B$
(b) If there are six protons, then it is carbon.
If there are eight neutrons and six protons, then there are fourteen nucleons.
If there are five electrons, then the charge is +1.
We can write the symbol for this ion:
$^{14}C^+$
