Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 36 - Relativity - Exercises and Problems - Page 1101: 69

Answer

The amount of energy released in each decay is $~~7.77\times 10^{-13}~J$

Work Step by Step

Note that $~~1~u = 1.66\times 10^{-27}~kg$ We can find the difference between the original mass and the final mass that remains after the decay: $226.0254~u-(222.0176~u+4.0026~u) = 0.0052~u$ This "missing mass" after the decay is the mass that has been converted into energy and released in the decay. We can calculate the energy: $E = mc^2$ $E = (0.0052)(1.66\times 10^{-27}~kg)(3.0\times 10^8~m/s)^2$ $E = 7.77\times 10^{-13}~J$ The amount of energy released in each decay is $~~7.77\times 10^{-13}~J$
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