Answer
Bolt 2 hit $~~2.0\times 10^{-5}~s~~$ earlier than bolt 1.
The assistant agrees that bolt 2 hit $~~2.0\times 10^{-5}~s~~$ earlier than bolt 1.
Work Step by Step
We can find the time it takes the light from bolt 1 to reach you:
$t = \frac{d}{c} = \frac{9000~m}{3.0\times 10^8~m/s} = 3.0\times 10^{-5}~s$
Since this light arrives at $t = 5.0\times 10^{-5}~s$, this bolt hit at $t_1 = 2.0\times 10^{-5}~s$
We can find the time it takes the light from bolt 2 to reach you:
$t = \frac{d}{c} = \frac{3000~m}{3.0\times 10^8~m/s} = 1.0\times 10^{-5}~s$
Since this light arrives at $t = 1.0\times 10^{-5}~s$, this bolt hit at $t_2 = 0$
Therefore, bolt 2 hit $~~2.0\times 10^{-5}~s~~$ earlier than bolt 1.
The assistant and you are in the same reference frame.
Therefore, the assistant agrees that bolt 2 hit $~~2.0\times 10^{-5}~s~~$ earlier than bolt 1.
