Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 35 - AC Circuits - Exercises and Problems - Page 1051: 3

Answer

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Work Step by Step

We know that the emf is given by $$\varepsilon=\varepsilon_0\cos\phi $$ where $$\phi=\omega t=2\pi f t$$ $$\varepsilon=\varepsilon_0\cos(2\pi f t) $$ Plug the known; $$\varepsilon=50\cos(2\pi \times 110 \times 3\times 10^{-3}) $$ $$\varepsilon= 50\cos119^\circ =\bf -24\;\rm V$$ See the graph below,
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