Answer
$\theta = 60^{\circ}$
Work Step by Step
We can use Malus' Law:
$I = I_0~cos^2~\theta$
$0.25~I_0 = I_0~cos^2~\theta$
$cos^2~\theta = 0.25$
$cos~\theta = \sqrt{0.25}$
$cos~\theta = 0.50$
$\theta = cos^{-1}~(0.50)$
$\theta = 60^{\circ}$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0321740904
ISBN 13:
978-0-32174-090-8
Chapter 34 - Electromagnetic Fields and Waves - Exercises and Problems - Page 1030: 25
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
