Answer
$I_d = 1.7\times 10^{-5}~A$
Work Step by Step
We can find the capacitance:
$C = \frac{\epsilon_0~A}{d}$
$C = \frac{\epsilon_0~\pi~r^2}{d}$
$C = \frac{(8.854\times 10^{-12}~F/m)~(\pi)~(0.025~m)^2}{0.50\times 10^{-3}~m}$
$C = 3.477\times 10^{-11}~F$
We can find the displacement current:
$I_d = C~(\frac{dv_c}{dt})$
$I_d = (3.477\times 10^{-11}~F)~(500,000~V/s)$
$I_d = 1.7\times 10^{-5}~A$
