Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 33 - Electromagnetic Induction - Exercises and Problems - Page 997: 23

Answer

The range of frequencies is from $~~2.5\times 10^5~Hz~~$ to $~~3.6\times 10^5~Hz$

Work Step by Step

We can find the lowest frequency: $f = \frac{1}{2\pi~\sqrt{LC}}$ $f = \frac{1}{2\pi~\sqrt{(2.0\times 10^{-3}~H)(200\times 10^{-12}~F)}}$ $f = 2.5\times 10^5~Hz$ We can find the highest frequency: $f = \frac{1}{2\pi~\sqrt{LC}}$ $f = \frac{1}{2\pi~\sqrt{(2.0\times 10^{-3}~H)(100\times 10^{-12}~F)}}$ $f = 3.6\times 10^5~Hz$ The range of frequencies is from $~~2.5\times 10^5~Hz~~$ to $~~3.6\times 10^5~Hz$
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