Answer
$v = 2.0\times 10^4~m/s$
Work Step by Step
We can find the required speed:
$emf =B~L~v$
$v =\frac{emf}{B~L}$
$v =\frac{1.0~V}{(5.0\times 10^{-5}~T)(1.0~m)}$
$v = 2.0\times 10^4~m/s$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0321740904
ISBN 13:
978-0-32174-090-8
Chapter 33 - Electromagnetic Induction - Exercises and Problems - Page 996: 1
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