Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 33 - Electromagnetic Induction - Conceptual Questions - Page 996: 12

Answer

The new frequency will be $~1000~Hz$

Work Step by Step

We can write an expression for the initial frequency: $f_1 = \frac{1}{2\pi~\sqrt{L_1~C}}$ We can find the new frequency: $f_2 = \frac{1}{2\pi~\sqrt{L_2~C}}$ $f_2 = \frac{1}{2\pi~\sqrt{4L_1~C}}$ $f_2 = \frac{1}{2}\times \frac{1}{2\pi~\sqrt{L_1~C}}$ $f_2 = \frac{1}{2}\times f_1$ $f_2 = \frac{1}{2}\times (2000~Hz)$ $f_2 = 1000~Hz$ The new frequency will be $~1000~Hz$
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