Answer
${\bf 0.025}\;\rm N\tag{Rightward}$
Work Step by Step
From the given graph, the direction of the current on the right side of the circuit is downward, and the direction of the uniform magnetic field is into the page.
So according to the right-hand rule, the direction of the force exerted on the right wire of this circuit is to the right.
Recalling that the force exerted on the wire by the magnetic field is given by
$$F=BIl\tag 1$$
Now we need to find the current in this circuit which is given by Ohm's law,
$$\varepsilon= IR$$
So,
$$I=\dfrac{\varepsilon}{R}$$
Plug into (1),
$$F=Bl\dfrac{\varepsilon}{R} $$
Plug the known;
$$F=(50\times 10^{-3})(0.10)\dfrac{15}{3} $$
$$F=\color{red}{\bf 0.025}\;\rm N\tag{Rightward}$$
