Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 918: 55

Answer

$R = 900\Omega$

Work Step by Step

Since same current flows through $R$ and $100\Omega$ so $ V_{out} = I*(100\Omega) = V{in}/10 $ $\implies I = \frac{V_{in}}{1000\Omega}$ and $ V_{out} = V_{in} - IR$ $\frac{V{in}}{10} = V_{in} - \frac{V_{in}}{1000\Omega}*R$ $\implies \frac{1}{1000\Omega}*R =\frac{9}{10} $ $\implies R = 900\Omega$
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