Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 3 - Vectors and Coordinate Systems - Exercises and Problems: 34

Answer

The component of the cannonball's velocity that is parallel to the ground is 86.6 m/s

Work Step by Step

The horizontal component of the velocity is parallel to the ground. Therefore; $v_x = v~cos(\theta)$ $v_x = (100~m/s)~cos(30^{\circ})$ $v_x = 86.6~m/s$ The component of the cannonball's velocity that is parallel to the ground is 86.6 m/s.
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