Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 3 - Vectors and Coordinate Systems - Exercises and Problems: 29

Answer

(a) At the end of the hike, the person is 100 meters lower compared to the starting point. (b) The magnitude of the net displacement is 5026 meters.

Work Step by Step

(a) The net vertical displacement is 200 m - 300 m which is -100 m. At the end of the hike, the person is 100 meters lower compared to the starting point. (b) We can add the two vectors to find the net displacement. $S_m+S_a = 500~m~east+5000~m~north-100~m~vertical$ We can find the magnitude $d$ of the net displacement: $d = \sqrt{(500~m)^2+(5000~m)^2+(-100~m)^2}$ $d = 5026~m$ The magnitude of the net displacement is 5026 meters.
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