Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 3 - Vectors and Coordinate Systems - Exercises and Problems: 18

Answer

$v_x = -50~m/s$ $v_y = -87~m/s$

Work Step by Step

The vector is directed at an angle which is $60^{\circ}$ below the negative x-axis in this coordinate system. Therefore: $v_x = -v~cos(\theta)$ $v_x = -(100~m/s)~cos(60^{\circ})$ $v_x = -50~m/s$ $v_y = -v~sin(\theta)$ $v_y = -(100~m/s)~sin(60^{\circ})$ $v_y = -87~m/s$
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