Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 29 - Potential and Field - Exercises and Problems - Page 862: 7

Answer

$Q = 3.0~C$

Work Step by Step

We can find the charge $Q$: $W = Q~\Delta V$ $Q = \frac{W}{\Delta V}$ $Q = \frac{27~J}{9.0~ V}$ $Q = 3.0~C$
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