Answer
$W = 1.6\times 10^{-13}~J$
Work Step by Step
We can find the amount of work done:
$W = Q~\Delta V$
$W = (1.6\times 10^{-19}~C)(1.0\times 10^6~V)$
$W = 1.6\times 10^{-13}~J$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0321740904
ISBN 13:
978-0-32174-090-8
Chapter 29 - Potential and Field - Exercises and Problems - Page 862: 6
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