Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 29 - Potential and Field - Conceptual Questions - Page 862: 11

Answer

We can rank the potential difference from largest to smallest: $\Delta V_3 \gt \Delta V_1 = \Delta V_4 \gt \Delta V_2$

Work Step by Step

We can write an expression for the potential difference in each case: $\Delta V_1 = \frac{Q}{C}$ $\Delta V_2 = \frac{Q}{2C} = \frac{1}{2}\times \frac{Q}{C}$ $\Delta V_3 = \frac{2Q}{C} = 2 \times \frac{Q}{C}$ $\Delta V_4 = \frac{2Q}{2C} =\frac{Q}{C}$ We can rank the potential difference from largest to smallest: $\Delta V_3 \gt \Delta V_1 = \Delta V_4 \gt \Delta V_2$
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