Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 29 - Potential and Field - Conceptual Questions - Page 861: 5

Answer

The electron moves to the right.

Work Step by Step

When an electron is released in an electric field, the electron moves toward positions of higher potential because the electron has a negative charge. We can find an expression for the electric force: $F = q~E$ $F = q~(-\frac{dV}{dx})$ At the point x = 2 m, $\frac{dV}{dx}$ is positive. Then $(-\frac{dV}{dx})$ is negative.Then the force $F$ is positive since the charge $q$ is negative. Therefore, the force on the electron is directed in the positive direction. The electron moves to the right.
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