Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 28 - The Electric Potential - Exercises and Problems - Page 837: 71

Answer

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Work Step by Step

$$\color{blue}{\bf [a]}$$ Two charges have a net charge of 40 nC, if you know that the potential energy between them is 90$\;\mu\rm J$ when they are 3 cm apart, what is the magnitude of the two charges? $$\color{blue}{\bf [b]}$$ Solving the first given formula for $q_1$; $$q_1=\dfrac{3\times 10^{-16}}{q_2}$$ Plug into the second given formula, $$\dfrac{3\times 10^{-16}}{q_2}+q_2=40\times 10^{-9}$$ Hence, $q_2=1\times 10^{-8}\;\rm C$ or $q_2=3\times 10^{-8}\;\rm C$ Therefore, the two charges are $\color{red}{\bf10}\;\rm nC$ and $\color{red}{\bf30}\;\rm nC$
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