Answer
(a) $\phi=0$
(b) $\phi=300\times 10^{-4}Nm^{2}/C=0.03Nm^{2}/C$
Work Step by Step
Given: $A= (2\times 3)\times 10^{-4}m^{2}y =6\times 10^{-4}m^{2}$ (plane xz)
(a) $E=100i+50k$
Electric flux $\phi$ through any surface is given as
$ \phi= E.A$
Thus, $\phi=(100i+50k)\times(6\times 10^{-4})j$
Hence, $\phi=0$
(b)
$E=100i+50j$
Electric flux $\phi$ through any surface is given as
$ \phi= E.A$
Thus, $\phi=(100i+50j)\times(6\times 10^{-4})j$
Hence, $\phi=300\times 10^{-4}Nm^{2}/C=0.03Nm^{2}/C$
