Answer
$E_1=E_2=E_3=E_4=E_5$
Work Step by Step
We know that the electric field inside an ideal capacitor is a uniform electric field and is given by
$$\vec E=\dfrac{\eta}{\epsilon_0}$$
And since the vectors between the two plates in the given figure are at the same length and direction, it is a uniform electric field.
Hence, the electric field is the same anywhere between the two plates. These two plates form an ideal capacitor.
Therefore,
$$E_1=E_2=E_3=E_4=E_5$$
