Answer
$q = 1.1\times 10^{-10}~C$
Work Step by Step
We can find the magnitude charge that creates a 1.0 N/C electric field at a point 1.0 m away:
$E = \frac{k~q}{r^2}$
$q = \frac{E~r^2}{k}$
$q = \frac{(1.0~N/C)(1.0~m)^2}{9.0\times 10^9~N~m^2/C^2}$
$q = 1.1\times 10^{-10}~C$
