Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 25 - Electric Charges and Forces - Exercises and Problems: 22

Answer

$q = 1.1\times 10^{-10}~C$

Work Step by Step

We can find the magnitude charge that creates a 1.0 N/C electric field at a point 1.0 m away: $E = \frac{k~q}{r^2}$ $q = \frac{E~r^2}{k}$ $q = \frac{(1.0~N/C)(1.0~m)^2}{9.0\times 10^9~N~m^2/C^2}$ $q = 1.1\times 10^{-10}~C$
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