Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 22 - Wave Optics - Exercises and Problems - Page 650: 26

Answer

$N = 30,470$

Work Step by Step

A new maximum is produced each time the mirror $L_2$ increases by a distance of $\frac{\lambda}{2}$ We can find the number of bright-dark-bright fringe shifts: $N = \frac{\Delta L_2}{\lambda/2}$ $N = \frac{2~\Delta L_2}{\lambda}$ $N = \frac{(2)~(1.0\times 10^{-2}~m)}{656.45\times 10^{-9}~m}$ $N = 30,470$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.