Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 21 - Superposition - Exercises and Problems: 6

Answer

$v = 30~m/s$

Work Step by Step

We can see that this is the fourth harmonic since there are 4 antinodes. We can find the wavelength. $\lambda = \frac{2L}{n}$ $\lambda = \frac{(2)(0.60~m)}{4}$ $\lambda = 0.30~m$ We can find the wave speed as: $v = f~\lambda$ $v = (100~Hz)(0.30~m)$ $v = 30~m/s$
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