Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 21 - Superposition - Exercises and Problems: 14

Answer

$v = 400~m/s$

Work Step by Step

The image shows the standing wave pattern for the second harmonic. We can find the speed of sound in the tube as: $v = f_2~\lambda_2$ $v = (f_2)~(\frac{2L}{2})$ $v = (500~Hz)(0.80~m)$ $v = 400~m/s$
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