## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson

# Chapter 20 - Traveling Waves - Exercises and Problems: 60

#### Answer

$v = \sqrt{\frac{Mg~sin(\theta)}{\mu}}$

#### Work Step by Step

The tension in the string is equal to the component of the block's weight directed down the slope. We can find the tension in the string as: $T = Mg~sin(\theta)$ We can find an expression for the speed of the waves on the string as: $v = \sqrt{\frac{T}{\mu}}$ $v = \sqrt{\frac{Mg~sin(\theta)}{\mu}}$

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